When equal volumes of 1.0 M HCl and 1.0 M NaOH are mixed together, they undergo a neutralization reaction to form water (H2O) and sodium chloride (NaCl). The balanced chemical equation for this reaction is:
HCl + NaOH → H2O + NaCl
Since the volumes and molarities of the reactants are equal, the reaction will go to completion, and all of the HCl and NaOH will be consumed.
The stoichiometry of the reaction is 1:1, meaning that for every 1 mole of HCl, 1 mole of NaOH is required to produce 1 mole of NaCl.
Let’s assume that we have V liters of each solution. The number of moles of HCl and NaOH in each solution can be calculated as follows:
Moles of HCl = Molarity × Volume = 1.0 M × V L = V moles
Moles of NaOH = Molarity × Volume = 1.0 M × V L = V moles
Since the reaction is 1:1, all of the HCl and NaOH will react to form V moles of NaCl.
The total volume of the resulting solution will be 2V liters (V liters of HCl solution + V liters of NaOH solution).
The concentration of NaCl in the resulting solution can be calculated as follows:
Concentration of NaCl = Moles of NaCl / Total Volume
Concentration of NaCl = V moles / 2V L
Concentration of NaCl = 0.5 M
So, the concentration of NaCl produced in the resulting solution will be 0.5 M.
Hence, the correct answer is option b. 0.5 M
When equal volumes of 1.0 M HCl and 1.0 M NaOH are mixed together, they undergo a neutralization reaction to form water (H2O) and sodium chloride (NaCl). The balanced chemical equation for this reaction is:
HCl + NaOH → H2O + NaCl
Since the volumes and molarities of the reactants are equal, the reaction will go to completion, and all of the HCl and NaOH will be consumed.
The stoichiometry of the reaction is 1:1, meaning that for every 1 mole of HCl, 1 mole of NaOH is required to produce 1 mole of NaCl.
Let’s assume that we have V liters of each solution. The number of moles of HCl and NaOH in each solution can be calculated as follows:
Moles of HCl = Molarity × Volume = 1.0 M × V L = V moles
Moles of NaOH = Molarity × Volume = 1.0 M × V L = V moles
Since the reaction is 1:1, all of the HCl and NaOH will react to form V moles of NaCl.
The total volume of the resulting solution will be 2V liters (V liters of HCl solution + V liters of NaOH solution).
The concentration of NaCl in the resulting solution can be calculated as follows:
Concentration of NaCl = Moles of NaCl / Total Volume
Concentration of NaCl = V moles / 2V L
Concentration of NaCl = 0.5 M
So, the concentration of NaCl produced in the resulting solution will be 0.5 M.
Hence, the correct answer is option b. 0.5 M